2/3^y=7x

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Solution for 2/3^y=7x equation: 


D( x )

3^y = 0

3^y = 0

3^y = 0

x należy do O

x in (-oo:+oo)

t_1 = 2/(3^y)

t_1-7*x = 0

t_1-7*x = 0 // - t_1

-7*x = -t_1 // : -7

x = -t_1/(-7)

x = t_1/7

x = (2/(3^y))/7

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